Как клонировать контрол TableLayoutPanel

Если вопрос актуален то можно так сделать

private void button1_Click(object sender, EventArgs e)
        {
            var y = new TableLayoutPanel()
            {
                RowCount = tableLayoutPanel1.RowCount,
                ColumnCount = tableLayoutPanel1.ColumnCount,
                Height = tableLayoutPanel1.Height,
                Width = tableLayoutPanel1.Width
            };
            for (int i = 0; i < tableLayoutPanel1.RowCount; i++)
            {
                RowStyle styleR = tableLayoutPanel1.RowStyles[i];
                y.RowStyles.Add(new RowStyle(styleR.SizeType, styleR.Height));
                for (int j = 0; j < tableLayoutPanel1.ColumnCount; j++)
                {
                    ColumnStyle styleC = tableLayoutPanel1.ColumnStyles[j];
                    y.ColumnStyles.Add(new ColumnStyle(styleC.SizeType, styleC.Width));
                }
            }
            var w = tableLayoutPanel1.Controls;
            for (int i = w.Count - 1; i >= 0; i--)
            {
                var c = w[i];
                y.Controls.Add(c, tableLayoutPanel1.GetColumn(c), tableLayoutPanel1.GetRow(c));
            }
            y.CellBorderStyle = TableLayoutPanelCellBorderStyle.Single;
            panel1.Controls.Add(y);
        }