Ошибка SQL Error Number: 1064 You have an error in your SQL syntax

327

02 декабря 2017, 07:06

Использую CI. Пытаюсь записать serialize() строку, но получаю ошибку

Error Number: 1064

You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'WHERE id = '1'' at line 4

UPDATE pages SET content = 'a:7:{s:5:\"dutch\";s:0:\"\";s:7:\"english\";s:17:\"regerg erg ergerg\";s:10:\"indonesian\";s:0:\"\";s:7:\"russian\";s:32:\"русиянский язык х\";s:18:\"simplified-chinese\";s:0:\"\";s:7:\"spanish\";s:0:\"\";s:7:\"turkish\";s:0:\"\";}', WHERE id = '1'

Filename: models/Pages_model.php

Line Number: 101

Строка для записи:

a:7:{s:5:"dutch";s:0:"";s:7:"english";s:17:"regerg erg ergerg";s:10:"indonesian";s:0:"";s:7:"russian";s:29:"русиянский язык";s:18:"simplified-chinese";s:0:"";s:7:"spanish";s:0:"";s:7:"turkish";s:0:"";}

Код model:

function edit_page($data = array())
    {
        if ($data)
        {
            $sql = "
                UPDATE {$this->_db}
                SET
                    content = " . ((is_array($data['content'])) ? $this->db->escape(serialize($data['content'])) : $this->db->escape($data['content'])) . ",
                WHERE id = " . $this->db->escape($data['id']) . "
            ";
            $this->db->query($sql);
            if ($this->db->affected_rows())
            {
                return TRUE;
            }
        }
        return FALSE;
    }

Благодарен за любую помощь!

Answer 1

Уберите запятую перед WHERE

$sql = "
            UPDATE {$this->_db}
            SET
                content = " . ((is_array($data['content'])) ? $this->db->escape(serialize($data['content'])) : $this->db->escape($data['content'])) . "
            WHERE id = " . $this->db->escape($data['id']) . "
        ";